#You are an input. You have value! You matter!
if number % 2 == 0
return "number is even" (is_num_even = 1 or true)
else
return "number is odd" (is_num_even = 0 or false)
modulo
pseudocode:
if number % 2 == 0 return "number is even" (is_num_even = 1 or true) else return "number is odd" (is_num_even = 0 or false)
plus you’d want an input validation beforehand
who needs modulo when you can get less characters out of
while (number > 1) { number -= 2; } return number;
very efficient
edit: or theres the trusty iseven api
here is somewhat less:
return (number % 2) == 0;
return !(number & 1);
This is the way. Modulo takes too long to compute, bitwise compare should be a lot faster.
return !(number & 0x1);
oh shit yo
this comment chain is pretty awesome, I learned a lot from this thanks!
just check the last bit jesus christ, what is it with these expensive modulo operations?!
return !(n&1);
are the negative numbers all even?
Yes
🤦
#You are an input. You have value! You matter! if number % 2 == 0 return "number is even" (is_num_even = 1 or true) else return "number is odd" (is_num_even = 0 or false)
Am I doing it right? /S.
Don’t put nbsps in code blocks, they show up literally.
Name doesn’t check out.
are u a wizard?
John carmak posting
This code is terrible. If you input 10.66 it returns "number is odd
It should be:
if number % 2 == 0 return "number is even" (is_num_even = 1 or true) else return "number is not even" (is_num_even = 0 or false)